9k^2+9k-504=0

Solution for 9k^2+9k-504=0 equation:

9k^2+9k-504=0

a = 9; b = 9; c = -504;
Δ = b2-4ac
Δ = 92-4·9·(-504)
Δ = 18225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18225}=135$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-135}{2*9}=\frac{-144}{18}
=-8
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+135}{2*9}=\frac{126}{18}
=7
$